Issue 17275: There is an inconsistency in the current spec between link equality and  link delete (mof2core-rtf)
Source: Model Driven Solutions (Mr. Steve Cook, steve-c(at)modeldriven.org)
Nature: 
Severity: 
Summary: There is an inconsistency in the current spec between link equality and  link delete.  Link equality only checks for the end values and the association, whereas link delete says: “This may leave the same elements associated by other links for this Association”, implying more than one distinguishable link per pair of elements.  This should be resolved according to the fact that in OCL and UML collections resulting from navigating associations can be bags, i.e. contain the same element more than once.  Links must be distinguishable individually, not simply by equality of their ends.   This will imply that links have some identity criteria: uuids would seem to fit the bill perfectly.

Resolution: 
Revised Text: 
Actions taken:
March 23, 2012: received issue
Discussion: 
Agreed. The resolution of this issue is dependent on a resolution to 17274, which is
deferred to allow more time and vendor involvement. This issue is therefore deferred
as well.
Disposition: Deferred
End of Annotations:=====
s is issue # 17275	From: Steve Cook <Steve.Cook@microsoft.com 

There is an inconsistency in the current spec between link equality and  link delete

There is an inconsistency in the current spec between link equality and  link delete.  Link equality only checks for the end values and the association, whereas link delete says: .This may leave the same elements associated by other links for this Association., implying more than one distinguishable link per pair of elements.  This should be resolved according to the fact that in OCL and UML collections resulting from navigating associations can be bags, i.e. contain the same element more than once.  Links must be distinguishable individually, not simply by equality of their ends.   This will imply that links have some identity criteria: uuids would seem to fit the bill perfectly.